Schaul v Jankovic
WTA Tour 2005
Lineball analyst0–13
Jelena Jankovic takes it, 13–0 on categories
Jankovic wins on first serve in %. WTA Tour 2005: Schaul 22 matches, Jankovic 67 matches.
- Jankovic has the better first serve in %: 66.3 to Schaul’s 48.3.
- Jankovic has the better first-serve points won %: 62.8 to Schaul’s 40.
- Jankovic has the better break points saved %: 59.8 to Schaul’s 40.6.
- Winners’ edge: Jankovic’s team won 57%, Schaul’s team won 27% of the matches they played.
- Longevity: Jankovic has 67 matches, Schaul 22 — the averages matter more than the totals here.
Built only from games in our stats database. A read of the numbers, not a tip.
Tale of the tape
Per game, with league rank among regular players.
- 48.3First serve in %66.3#14 of 90
- 40.0First-serve points won %62.8#36 of 90
- 40.6Break points saved %59.8#15 of 90
- 41.7Return points won %46.2#35 of 90
- 0.11 total · best 1Acesper game0.425 total · best 8#48 of 90
- 8.2181 total · best 16Games wonper game11.3760 total · best 18
Head to head
13 matches
since 20042
since 20042
- Hard · 3 matchesSchaul 1Jankovic 2
Last meetings
- 3 Jan 2005 · Auckland · Round of 32 · HardJankovic won 7-5 6-2
- 24 Mar 2004 · Miami · Round of 128 · HardJankovic won 6-1 5-7 6-3
- 10 Mar 2004 · Indian Wells · Round of 128 · HardSchaul won 7-6(9) 6-4
Last 10 games
First serve in %, oldest to newest in 2005.
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