Levy v Teran
WTA Tour career
Megan Moulton LevyUnited States8 games · 2003–2004
Maria Fernanda Alvarez TeranBolivia35 games · 2003–2019Lineball analyst6–0
Megan Moulton Levy takes it, 6–0 on categories
Moulton Levy wins on sets lost. WTA Tour career: Moulton Levy 8 matches, Fernanda Alvarez Teran 35 matches.
- Moulton Levy averages a sets lost every 2 matches to Fernanda Alvarez Teran’s 1.1.
- Moulton Levy averages 4.9 games lost a match to Fernanda Alvarez Teran’s 9.9.
- Moulton Levy has the better sets won %: 76.5 to Fernanda Alvarez Teran’s 51.9.
- Winners’ edge: Moulton Levy’s team won 75%, Fernanda Alvarez Teran’s team won 51% of the matches they played.
- Longevity: Fernanda Alvarez Teran has 35 matches across 11 seasons, Moulton Levy 8 in 2 — the averages matter more than the totals here.
- Small sample: Moulton Levy (8 matches) — treat the averages with care.
- Not every stat was recorded for every match (aces, double faults, serve points…): those averages use only the games that logged them.
Built only from games in our stats database. A read of the numbers, not a tip.
Tale of the tape
Per game. Totals and best single game underneath.
- –First serve in %56.0
- –First-serve points won %70.6
- –Break points saved %63.2
- –Return points won %32.9
- –Acesper game24 total · best 3
- 11.189 total · best 12Games wonper game9.8343 total · best 17
- 76.5Sets won %51.9
Head to head
11 match
since 20030
since 20030
- Hard · 1 matchLevy 1Teran 0
Last meetings
- 24 Apr 2003 · Fed Cup G2 RRB: JAM vs BOL · Round robin · HardLevy won 6-2 6-1
Last 10 games
First serve in %, oldest to newest.
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